Learn R Programming

dendextend (version 1.1.2)

labels<-: "label" assignment operator

Description

"label" assignment operator for vectors, dendrogram, and hclust classes. # '

Usage

labels(object, ...) <- value


## S3 method for class 'dendrogram':
labels(object, ...) <- value

## S3 method for class 'hclust':
labels(object, order = TRUE,...)

## S3 method for class 'hclust':
labels(object, ...) <- value

## S3 method for class 'phylo':
labels(object, ...)

## S3 method for class 'phylo':
labels(object, ...) <- value

## S3 method for class 'hclust':
labels(object, order = TRUE, ...)

## S3 method for class 'hclust':
labels(object, ...) <- value

Arguments

object
a variable name (possibly quoted) who's label are to be updated
...
parameters passed (not currently in use)
value
a value to be assigned to object's label
order
default is FALSE. Only relevant for extracting labels from an hclust object (with labels.hclust). Setting order=TRUE will return labels in their order in the dendrogram, instead of the riginal labels order retained fr

Value

  • The updated object

source

The functions here are based on code by Gavin and kohske from (adopted to dendrogram by Tal Galili): http://stackoverflow.com/questions/4614223/how-to-have-the-following-work-labelsx-some-value-r-question Also with some ideas from Gregory Jefferis's dendroextras package.

Details

###################

See Also

labels

Examples

Run this code
x <- 1:3
labels(x)
labels(x) <- letters[1:3]
labels(x) # [1] "a" "b" "c"
x
# a b c
# 1 2 3


# get("labels<-")

################
# Example for using the assignment with dendrogram and hclust objects:
hc <- hclust(dist(USArrests[1:3,]), "ave")
dend <- as.dendrogram(hc)

labels(hc) # "Arizona" "Alabama" "Alaska"
labels(hc)  <- letters[1:3]
labels(hc)# "a" "b" "c"
labels(dend) # "Arizona" "Alabama" "Alaska"
labels(dend) <- letters[1:3]
labels(dend) # "a" "b" "c"
labels(dend) <- LETTERS[1:2] # will produce a warning
labels(dend) # "A" "B" "A"
labels(dend) <- LETTERS[4:6] # will replace the labels correctly
# (the fact the tree had duplicate labels will not cause a problem)
labels(dend) # "D" "E" "F"

Run the code above in your browser using DataLab